Question

answer these all questions with explaining how you got the answer with full proper solution please it's urgent send me all answers please​

Answer 1

Answer:

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1) answer

tanA=cotB

for suppose

tan60°=cot30°

now

A+B=60°+30°

=90°(A)

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2)answer

sin²36°+cos²36°

it is in the form of sin²θ+cos²θ=1

then sin²36°+cos²36°=1(B)

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3)answer

45°→radians

we know that

$</p><p>\frac{D}{90}=\frac{g}{100}=\frac{2C}{\pi}$

$\frac{D}{90}=\frac{2C}{\pi}$

now substitute

$\frac{45}{90} = \frac{2c}{\pi} \\ \\ \frac{1}{2} = \frac{2c}{\pi} \\ \\ \frac{\pi}{4} = c$

${\boxed{\mathsf\purple{45°= \frac{ {\pi}^{c} }{4} }}}$

(B)

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given that

8tanθ=15

tanθ=15/8

$\frac{1}{ \cot(\theta) } = \frac{15}{8} \\ \\ \cot(\theta) = \frac{8}{15}$

(A)

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5) answer

sin45°=cos45°

1/√2=1/√2

now θ=45°

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hope this helps you please mark it as brainliest answer