Question

answer these please if nonsense answers I will report their answers​

Answer 1

Answer:

1-c

2-b

3-a

4-c

5-b

6-b

7-c

Answer 2

Step-by-step explanation:

Solutions :-

1)Given number is (-3)^-4

=> 1/(-3)⁴

Since a^-n = 1/a^n

=>1/(-3×-3×-3×-3)

=> 1/81

(-3)^-4 = 1/81

2) Given number = [{(-4/9)^3}^-2]^-1

=> (-4/9)^(3×-2×-1)

Since (a^m)^n = a^(mn)

=> (-4/9)^6

[{(-4/9)^3}^-2]^-1 = (-4/9)^6

3) Given number = (-3/5)^-6 ÷ (-3/5)^-2

=> (-3/5)^[-6-(-2)]

Since a^m / a^n = a^(m-n)

=> (-3/5)^(-6+2)

=>(-3/5)^-4

(-3/5)^-6 ÷ (-3/5)^-2 = (-3/5)^-4

4) Given number = (3/4)^-3

=>1/(3/4)^3

Since a^-n = 1/a^n

=> (4/3)^3

=>(4×4×4)/(3×3×3)

=>64/27

(-3/4)^-3 = 64/27

5)Given number = 5×10^-2

=> 5×(1/10^2)

Since a^-n = 1/a^n

=> 5×(1/100)

=> 5/100

=> 0.05

5×10^-2 = 0.05

6)Given number = (-6/5)^-1

=> 1/(-6/5)

Since a^-n = 1/a^n

=> -5/6

(-6/5)^-1 = -5/6

7) Given number = (5/12)^0

=> 1

Since a^0 = 1

(5/12)^0 = 1

Answer:-

1.c

2.b

3.a

4.c

5.b

6.b

7.d

Used formulae:-

• a^-n = 1/a^n

• a^m / a^n = a^(m-n)

• a^0 = 1

• (a/b)^m = a^m / a^n