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TejasChaudhari192:
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pa=x
pb=x
ab=x+x/2=(2x+x)/2=3x/2
perimeter of triangle pab=ab+bc+ac=98
x+x+3x/2=98
( 2x+2x+3x)/2=98
7x=98×2=x=196/7=28cm
pa=pb=28cm
ab=3x/2=3(28)/2=3×14=42cm
am=ab/2=42/2=21
(pa)^2=(pm)^2+(am)^2
(28)^2=(pm)^2+(21)^2
784-441=(pm)^2
343 =(pm)^2
(18.2)^2=(pm)^2
pm=18.2cm
pb=x
ab=x+x/2=(2x+x)/2=3x/2
perimeter of triangle pab=ab+bc+ac=98
x+x+3x/2=98
( 2x+2x+3x)/2=98
7x=98×2=x=196/7=28cm
pa=pb=28cm
ab=3x/2=3(28)/2=3×14=42cm
am=ab/2=42/2=21
(pa)^2=(pm)^2+(am)^2
(28)^2=(pm)^2+(21)^2
784-441=(pm)^2
343 =(pm)^2
(18.2)^2=(pm)^2
pm=18.2cm
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