Question

answer these questions​

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be a square.

AB = BC = CD = DA

By Pythagoras theorem,

$AB^{2}$ + $AD^{2}$ = $BD^{2}$

$AD^{2}$ + $DC^{2}$ = $AC^{2}$

(AB = DC)

$DC^{2}$ + $AD^{2}$ = $BD^{2}$

$AD^{2}$ + $DC^{2}$ = $AC^{2}$

Therefore, we get

$BD^{2}$ = $AC^{2}$