answer these questions
Attachments:
Answers
Answered by
2
1. Assuming x+1 , x+3 and x+5 are the consecutive odd nos
x+1+x+3+x+5= 63
3x+9=63
3x=54
x=18
x+1+x+3+x+5= 63
3x+9=63
3x=54
x=18
Answered by
0
let the numerator be x-6
denominator be x
if 3 is added to numerator
x-6+3/x= 2/3
2x=3x-18
x=18
original fraction=12/18=2/3
denominator be x
if 3 is added to numerator
x-6+3/x= 2/3
2x=3x-18
x=18
original fraction=12/18=2/3
Similar questions