Question

answer these questions correctly

Answer 1

numbers 31 - 50 are written on chits of paper and dropped in a  box 

que 7) / ans a => dude probablity of multiples of 10 is there are 2 multiple of 10 between 31 - 50  which are 40 and 50 
and there are 19 no between 31-50 *_* 
so probability is given by => no of observation / total no  of observation
probability = 2/19 

ans b)=> here are 31 , 32 ,33 , 34 , 35 , 36 , 37, 38 ,39 , 40 , 41 , 42 , 43 , 44 , 45 , 46 , 47 , 48 , 49 ,50 numbers 
so  in these numbers even numbers are 
32 , 34 , 46 , 48 , 40 , 42 , 44 , 46 , 48 , 50  so total no of even numbers are = 10 
so probabiblity of choosing even numbers is given by = no of observation / total no 
= > dude 10 / 19 

ans c) => prime numbers are = 31 ,37 ,38 , 41 , 43 , 46 , 47,49 are prime numbers between 31 to 50 dude now so total no of prime numbers between 31 to 50 are = 8
so dude probability of event = no of observation / total number of outcomes 
= 8 /19 
que 8) / ans8)=> total no of balls in a box = 10 
2balls are yellow 3 balls are red and remaining 5 are green 
so here we can find the probability by 

a ) probability of red balls = total no of red balls / total no of balls =.> 2/10 = 1/5 
b) probability of yellow balls = total no of yellow balls / total no of balls => 3/10 
c) probability of green balls = total no of green balls / total no of balls => 5/10 = 1/2 

que9) /answer ..................................... -: 
if a dice is rolled 
1) =>     probability of getting number 2 =total no of 2 in sample space / total no of dice have = 1/6 
2)=> probability of getting number 5=> total no of 5 in sample space /total no of dice have = 1 /6 
3) => numbers which are less than 4 in a dice are 1 , 2 ,3 so here no of sample space = 3 so probability numbers which are less than 4 =total number of sample space /total no of dice have= > 3/6 = 1/2 dude *_* 

4) multiple of 2 in a dice are => 2 ,4 , 6 so probability of getting multiple of 2 is => total no of multiple of 2 / total number of dice have = 3 / 6= 1/2 

5) => total odd number in a  dice are => 1,3,5 so here dude we can find the probability again by = total odd number in a dice / total number of dice have = > 3/6= 1/2 

6)=> even numbers in a dice are 2,4,6 so probability of getting even numbers => total even numbers in a dice /total number in a dice = 3/6=1/2 

7)=> here are no composite number in a dice so probability is zero 

8)=>probability of getting any number = any number / total number = 1/6 

que 10)/answer ) => sniper has numbers marked as  1 to 10 
 
1)=> prime numbers between 1 to10 are 1 ,2 ,3 ,5 ,7 so here are 5 prime no between  1 to 10 dude 
so probability of getting prime numbers between 1 to 10 is = total number of prime numbers between 1to 10 / total number of outcomes = 5/10 = 1/2 

2)=> total number of square numbers between 1 to 10 are only  1 ,4 , 9 
so here we can find the probability of getting square number => total number of square number between 1  to 10 / total numbers = 3 /10 

dude have any doubt ask in comment section ^_^ study hard 

Answer 2

probability of multiples of 10 is there are 2 multiple of 10 between 31 - 50  which are 40 and 50 

and there are 19 no between 31-50 *_* 

so probability is given by => no of observation / total no  of observation

probability = 2/19 

ans b)=> here are 31 , 32 ,33 , 34 , 35 , 36 , 37, 38 ,39 , 40 , 41 , 42 , 43 , 44 , 45 , 46 , 47 , 48 , 49 ,50 numbers 

so  in these numbers even numbers are 

32 , 34 , 46 , 48 , 40 , 42 , 44 , 46 , 48 , 50  so total no of even numbers are = 10 

so probabiblity of choosing even numbers is given by = no of observation / total no 

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