Question

answer these questions fast​

Answer 1

Answer:

Step-by-step explanation:

{sec}^{2}  \theta +  {cosec}^{2}  \theta =  {sec}^{2}  \theta. {cosec}^{2}  \theta

L.H.S.

=  \frac{1}{ {cos}^{2}  \theta}  +  \frac{1}{ {sin}^{2}  \theta}  \\  =  \frac{ {sin}^{2}  \theta \:  +  {cos}^{2}  \theta}{ {cos}^{2} \theta. {sin}^{2}  \theta }  \\  =   \frac{1}{ {cos}^{2}  \theta. {sin}^{2} \theta }  \\  =  {sec}^{2}  \theta. {cosec}^{2}   \theta

= R.H.S.

Answer 2

Answer:

bhaiya itne saare question ke jawab kon dega

koi pick karke bata dena mere question pe aake

tab keval utne solve kar dunga

is answer ko edit karke