Answer these two questions fast. it's very important.
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angle q =60[vertically opp. angles]
angle p+60=180[leniar pair]
p=180-60
p=120
sum of all angles of any polygon is
(n-2)X180
where n is the no. of sides
sum of octagon=(8-2)X180
=6X180
=1080
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no me
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In question 5
the value of p
p+60=180 ....... angles in linear pair
p= 180- 60
p= 120
q=60 ....... opposite angles
the value of p
p+60=180 ....... angles in linear pair
p= 180- 60
p= 120
q=60 ....... opposite angles
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