answer these two questions please
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Let us consider (a),
<PAC= <PDB ( <PDB + <CAB = 180 = <CAB + <CAP implies, <CAP = <PDB>
<APC = <BPD (common)
therefore, triangles are congruent by AA ~ criteria.
Consider (b)
<APC = <BPD (Vertically opp. angles)
<CAP = BDP (angles in the same segment)
therefore, the two triangles are similar(By AA similarity criteria).
<PAC= <PDB ( <PDB + <CAB = 180 = <CAB + <CAP implies, <CAP = <PDB>
<APC = <BPD (common)
therefore, triangles are congruent by AA ~ criteria.
Consider (b)
<APC = <BPD (Vertically opp. angles)
<CAP = BDP (angles in the same segment)
therefore, the two triangles are similar(By AA similarity criteria).
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