Question

answer these two questions please​

Answer 1

Solution for Q16
in triangle TQR
angleTQR + angleQTR + angleQRT = 180 degree(angle sum property)
40+90+x=180
130+x=180
x=180-130
x=50 degree

Answer 2

Answer:

Step-by-step explanation:

In TQR

40+X+90=180

X=180-130

X=50

In PSR

50+30+PSR =180

PSR=100

PSQ+PSR=180(l.p.)

y+100=180

y=80