Math, asked by rekhadhiman1830, 8 months ago

Answer these with full solution. irrelevant answer will be reported . ​

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Answered by spacelover123
2

11. ((\frac{1}{2} )^{-1} + (\frac{2}{3}) ^{2} - (\frac{3}{4})^{0} )^{-2}

First, we will apply the zero power rule and the negative exponent inside the bracket.

Zero Power Law ⇒ a^{0 } = 1

Negative Power Law ⇒ a^{-1} = \frac{1}{a}

((2)+(\frac{2}{3})^{2}  - 1)^{-2}

Now we will substitute the values and give a whole value to all numbers.

(2+\frac{4}{9} -1)^{-2} =   (\frac{13}{9})^{-2} = (\frac{9}{13})^{2}

Now we can find the value of (\frac{9}{13})^{2} which is \frac{81}{169}.

12. (1^{2}+2^{2} + 3^{2})^{\frac{1}{2} }

First, we will find the value of the numbers in the brackets.

(1+4+9)^{\frac{1}{2} } = (14)^{\frac{1}{2} }

(14)^{\frac{1}{2} } = \sqrt{14}

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