Question

answer this..........​

Answer 1

Step-by-step explanation:

Given: y = sin²(3x)

1st derivative:

$\Rightarrow \frac{d}{dx}(sin^2(3x))$

To apply the chain rule, set u as sin(3x), then f = u²

$\Rightarrow \frac{d}{du}(u^2)\frac{d}{dx}(sin(3x))$

$\Rightarrow 2u * cos(3x) * 3$

$\Rightarrow 2ucos(3x)*3$

$\Rightarrow 2sin(3x)cos(3x)*3$

$\Rightarrow sin(2*3x)*3$

$\Rightarrow \boxed{3sin(6x)}$

Hope it helps!

Answer 2

By using the power rule and other rules, we get

d/dxsin^2(3x)=2sin3x*(cos3x)*3