Question

answer this...........​

Answer 1

${} \huge \mathfrak \red{solution - }$

In ∆CDE,

∠CDE + ∠DCE = CEB (Exterior angle)

∠CDE + 20° = 130°

∠CDE = 110°

However, ∠BAC = ∠CDE (Angles in the same segment of a circle)

∠BAC = 110°

As angles in same segment are equal.

So,

∠BAC = ∠BDC =110°

Answer 2

Step-by-step explanation:

$angle \: ced = 50(linear \: pair) \\ dec = 110(angle \: sum \: property \: of \: triamngle) \\ bac = bdc = 110$

property in class 10 that the angle on same point or on the same line are equal.

so angle bac=110 degree