Question

Answer this............​

Answer 1

Step-by-step explanation:

▪️In ∆ABC and ∆DCB,

▪️AC = DB [Given]

▪️AB = DC [Opposite sides of a parallelogram]

▪️BC = CB [Common]

▪️∴ ∆ABC ≅ ∆DCB [By SSS congruency]

▪️⇒ ∠ABC = ∠DCB [By C.P.C.T.] …(1)

▪️Now, AB || DC and BC is a transversal.

▪️[ ∵ ABCD is a parallelogram]

▪️∴ ∠ABC + ∠DCB = 180° … (2) [Co-interior angles]

▪️From (1) and (2), we have

▪️∠ABC = ∠DCB = 90°

▪️i.e., ABCD is a parallelogram having an angle

equal to 90°

▪️∴ ABCD is a rectangle.

Hopes it help you✌️✌️

Answer 2

Answer:

$Hope \: \: the \: \: above \: \: attachment \: \: helps \: \: you \: \: .$