Question

answer this!!!!!!!!!!!!!!​

Answer 1

$\: \: \: \: \: \: \: \: \star\bf\: \: \: {Required\: figure}$

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Given:-

• Radius of smaller circle = 3cm
• Radius of larger circle = 5cm

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To find:-

• Length of chord of the larger circle.

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Solution:-

• According to the figure, we need to find the length of PQ.

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★ As we can see that ∆OAP is a right angled triangle.

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Therefore, in triangle OAP.

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$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{By\: using\: Pythagoras\: theorem}}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {OP^2 = OA^2 + AP^2}$

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$\tt:\implies\: \: \: \: \: \: \: \: {(5)^2 = (3)^2 + AP^2}$

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$\tt:\implies\: \: \: \: \: \: \: \: {25 = 9 + AP^2}$

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$\tt:\implies\: \: \: \: \: \: \: \: {AP^2 = 25 - 9}$

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$\tt:\implies\: \: \: \: \: \: \: \: {AP^2 = 16}$

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$\tt:\implies\: \: \: \: \: \: \: \: {AP = \sqrt{16}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {AP = 4\: cm}$

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As we can see in the figure, that OA is the perpendicular bisector of PQ.

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$\star{\boxed{\sf{\orange{PQ = 2AP}}}}$

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$\tt\longrightarrow{PQ = 2 \times 4}$

$\tt\longrightarrow{PQ = 8\: cm}$

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Therefore,

The length of chord of the larger circle is 8cm.

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Hence,

Option (c) is the correct option.