Answer this ⬆️
:)))))))))))))))
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Answer:
a coin is tossed:
S: { T,H}
n(S): 2
event A: getting a tail
A: {T}
n(A): 1
p(A): n(A)/ n(S)
= 1/2
event B: not getting a tail:
B:{H}
n(B): 1
p(B): n(B)/n(S)
= 1/2
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