Question

answer this....................

Answer 1

This is the case of horizontal projectile.

Given, initial velocity , u = 10 m/s

height , h = 20m

use the formula,

Horizontal range , X = u√(2h/g)

So, X = 10 × √{2 × 20/10}

X = 20m

Hence, horizontal distance covered by object is 20 m

#####J3

Answer 2

This is the case of horizontal projectile.

Given, initial velocity , u = 10 m/s

height , h = 20m

use the formula,

Horizontal range , X = u√(2h/g)

So, X = 10 × √{2 × 20/10}

X = 20m

Hence, horizontal distance covered by object is 20 m