Question

answer this
a) Define an ideal electric dipole. Give an example.

b) Derive an expression for the torque experienced by an electric

dipole in a uniform electric field. What is net force acting on this

dipole.

c) An electric dipole of length 2cm is placed with its axis making an

angle of 600

with respect to uniform electric field of 105

N/C.

If it experiences a torque of 8√3 Nm, calculate the (i) magnitude of

charge on the dipole, and its potential energy.
plz read the question carefully and answer faster​

Answer 1

Answer:

your amswer (b) An electric dipole of length 2cm placed with axis making an angel of 600

Answer 2

Ideal Dipole:

• An arrangement of equal positive af negative charges separated by a small distance.

• Example : H-Cl molecule

Let torque be $\tau$, dipole moment be P, electrostatic field intensity be E and $\theta$ is the angle between r vector and F vector.

$\therefore \: | \tau | = r \times F \times \sin( \theta)$

$\implies \: | \tau | = d\times (qE) \times \sin( \theta)$

$\implies \: | \tau | = (q \times d)\times E \times \sin( \theta)$

$\boxed{\implies \: | \tau | = P\times E \times \sin( \theta) }$

• Net force acting on the dipole is zero.

c) Calculation of charge ?

$\boxed{\implies \: | \tau | = P\times E \times \sin( \theta) }$

$\implies \: 8 \sqrt{3} = (q \times \frac{2}{100}) \times {10}^{5} \times \sin( {60}^{ \circ} )$

$\implies \: 8 \sqrt{3} = (q \times \dfrac{2}{100}) \times {10}^{5} \times \dfrac{ \sqrt{3} }{2}$

$\implies \: 8 = (q \times \dfrac{2}{100}) \times {10}^{5} \times \dfrac{1}{2}$

$\implies \: 8 = (q \times \dfrac{1}{100}) \times {10}^{5}$

$\implies \: 8 = q \times {10}^{ 3}$

$\implies \: q = 8 \times {10}^{ - 3} \: C$

$\implies \: q = 8 \: mC$

So, charge is 8 mC.