Question

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FIND THE FACTOR OF THIS EQUATION​

Answer 1

$ax^{2} +( {4a}^{2} −3b)x−12ab \\ = ax {}^{2} +4ax {}^{2} −3bx−12ab \\ = ax(x+4a)−3b(x+4a) \\ =  (ax−3b)(x+4a)$

Answer 2

Step-by-step explanation:

Given :-

ax²+(4a²-3b)x - 12ab

To find :-

Find the factors of the expression ?

Solution :-

Given expression is ax²+(4a²-3b)x - 12ab

=> ax²+4a²x-3bx-12ab

=> ax (x + 4a) - 3b (x + 4a)

=> (x + 4a)(ax - 3b)

The factorization of ax²+(4a²-3b)x - 12ab is

(x + 4a)(ax - 3b)

Factors are (x+4a) and (ax-3b)

Answer:-

ax²+(4a²-3b)x - 12ab = (x + 4a)(ax - 3b)

Factors are (x+4a) and (ax-3b)

Used Method:-

• Splitting the middle term

Points to know:-

• Writting the number or expression as the product of factors is called factorization.
• 1 is a factor of every number .