Question

answer this and I'll mark as a brainlists ​

Answer 1

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Refer to the attachment for further assistance.........

Name all the points as A, B, C, D

now from the BAD make a LINE bisecting it

so BAO=DAO

Now in ∆BOA

BO = OA (Both are the radius)

ABO = OAB (angle opposite to equal sides are equal)

so ABO = BAO
32° = 32° 【i】


Now in ∆AOD

OA = OD (Both are the radius)

OAD = ODA (angle opposite to equal sides are equal)

SO OAD = ADO
41° = 41° 【ii】


BAD = BAO + OAD

from (i) and (ii)

BAD = 32° + 41°

BAD = 73°

but
"all the points are on circle hence it is cyclic quadrilateral"

BAD+BCD= 180°

73°+BCD=180°

BCD = 180°-73°

BCD = 107°

hence y = 107°