Question

Answer this and I'll mark you the brainliest...​

Answer 1

Answer:

Ac is 16 cm mark as brainliest

Answer 2

Answer:

AC = 20cm.

BC = 24cm

Step-by-step explanation:

(i) In ∆ABC, DE||BC.

According to Thales Theorem, AD/DB = AE/EC the ratios must be same.

So,

Given AD = 6cm

DB = 9cm

AE = 8cm

AD/DB = AE/EC (By Thales Theorem)

6/9 = 8/EC

2/3 = 8/EC

2EC = 24 (Cross Multiplication)

EC = 12cm.

Now,

For AC

AC = AE + EC

AC = (8 + 12)cm.

AC = 20cm.

(ii) In ∆ABC, angle C = 90°, AB = 25cm, AC = 7cm.

So,

*AB = 25cm = Hypotenuse of Triangle.

*AC = 7cm = Perpendicular of Triangle.

*BC = To find = Base of Triangle.

Now, Using Pythagoras Theorem.

Pythagoras Theorem: Hypotenuse^2 = Perpendicular^2 + Base^2

AB^2 = AC^2 + BC^2

(25)^2 = (7)^2 + BC^2

625 = 49 + BC^2

625-49 = BC^2

576 = BC^2

BC = √576cm

BC = 24cm.