Question

answer this argent plz

Answer 1

use identity (a+b+c)^2

Answer 2

[1/4 a - 1/2b + 1]^2

Solving it, we get : (1/4a)^ 2+(1/2b)^2 + 1^2 - 2(1/4+1/2) - 2( 1/2 + 1) + 2( 1/4 + 1)

1/16a^2 + 1/4b^2 + 1 -3/2 - 3 + 5/2

1/16a^2 + 1/4b^2 -2 + 2/2

1/16a^2 + 1/4b^2 -2 + 1

1/16a^2 + 1/4b^2 - 1

Here the common factor is 1/16

So, factorising...Answer : 1/16 ( a^2 + 4b^2 - 16)

Hope it helps!

Please mark as Brainliest!

(Please correct me if I am wrong)