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p(e)=no. of favourable outcomes/total no. of outcomes
total number of outcomes when a coin is tossed 3 times : 2*2*2 = 8
the two outcomes H or T for each toss is independent of other tosses. So they are multiplied.
Two outcomes give winning combination = 3 H or 3 T..
Hence probability of failure
= (8-2)/8 = 3/4
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