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Answer:(1/2) abSinC
Step-by-step explanation:
,if a,b and c are the length of sides of triangle ABC,then prove that area of triangle is equal to 1/2ab sinc
AB = c
BC = a
AC = b
∠C is angle between BC & AC
Now lets draw AD perpendicular from Vertex A at BC
Now area of Triangle = (1/2) * BC * AD
= (1/2) a * AD
in Δ ACD
Sin∠C = Perpendicular / Hypotenuse
=> Sin C = AD/AC
=> SinC = AD/b
=> AD = bSinC
putting this in area
area of Triangle = (1/2) a * bSInC
= (1/2) abSinC
Hence Proved
QED
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