Question

Answer this both question no spam.


1. In a mathematics test given to 15 students, the following marks ( out of 100)
are recorded.

41 , 39 , 48 , 52 , 46 , 62 , 54 , 40 , 96 , 52 , 98 , 40 , 42 , 52 , 60

find the mean , median, and mode of this data.


2. The following observations have been arranged in ascending order. it the median of the data is 63 , find the value of x.

29 , 32 , 48 , 50 , x, x + 2 ,72, 78 , 84 , 95


no copied, correct✅ answer needed
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Answer 1

Answer:

Ex14.4, 2 teachoo.com In a mathematics test given to 15 students, the following marks (out of 100) are recorded: 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60 Find the mean, median and mode of this data. Mean Mean of data = Sum of all observation Number of observation 41 +39 +48 +52 +46 +62 +54 +40+96 +52 +98 +40 +42 +52 + 60 15 822 = = 54.8 15 Median Arranging data in ascending order, 39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98 Number of observations = n = 15 (odd number) Median = ("+1) th observation

Answer 2

question 1: In a mathematics test given to 15 students, the following marks ( out of 100)

are recorded.

41 , 39 , 48 , 52 , 46 , 62 , 54 , 40 , 96 , 52 , 98 , 40 , 42 , 52 , 60

$\red{Solution}$

The marks of 15 students is

41,39,48,52,46,62,54,40,96,52,98,40,42,52,60

Mean =

$\frac{41+39+48+52+46+62+54+40+96+}{15}$

$\frac{825}{15} = 54.8;$

Number of observations =15 (odd)

Median score =8th number arranging in ascending order which is 52.

Maximum frequency =3 of 52

∴ Mode =52. .

question 2: The following observations have been arranged in ascending order. it the median of the data is 63 , find the value of x.

29 , 32 , 48 , 50 , x, x + 2 ,72, 78 , 84 , 95

$\red{Solution}$

Total observations =10 (even)

Median =

$\frac{10}{2} = {5}^{th} \: and \frac{10}{2} + 1 \: = \: {6}^{th}$

observations

Median =

$\frac{ {5}^{th \: + {6}^{th \: observation} } }{2}$

$63 = \frac{x + x + 2}{2}$

⇒x+1=63

⇒x=62