Question

answer this correctly
whoever answer this first I will follow him or her​

Answer 1

Answer:u=3 m/s

a=0.6 ms^-2

t=3 sec

distance travelled in first 3 sec, s= ut+1/2 a t^2

                                                      =3*3+1/2*0.6*9=9+2.7=11.7

time taken to reach velocity 9m/s

v=u+at

(v-u)/a=t

t= 9-3/0.6=6/0.6=10 sec

Explanation:if it helps mark as brainliest