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Ram and Nisha both draw a rectangle each. The length of both the rectangles is 4 cm. The breadth of Nisha’s rectangle is 3/2 times the breadth b, of Ram’s rectangle. Which of these expressions represents the PERIMETER of Nisha’s rectangle?

a) 2( 4 +b) b) 2( 4 +6b) c) 2(4 +32 ) d) 2( 32+4b)

Answers

Answered by Debrajm
37

Answer:

Step-by-step explanation:

Attachments:
Answered by Anonymous
126

AnswEr :

\tt{Ram's \:  Rectangle} \begin{cases}\sf{Length=4 \: cm} \\ \sf{Breadth=b\: cm}\end{cases}

\tt{Nisha's \:  Rectangle} \begin{cases}\sf{Length=4 \:cm} \\ \sf{Breadth=\dfrac{3}{2} \times b} =  \dfrac{3b}{2} \:cm \end{cases}

Perimeter of Nisha's Rectangle :

\implies \tt Perimeter = 2 \times (Length+ Breadth)

\implies \tt Perimeter = 2 \times \bigg(4 + \dfrac{3b}{2} \bigg)

\implies \tt Perimeter = 2 \times \bigg(\dfrac{(4 \times 2) + 3b}{2} \bigg)

\implies \tt Perimeter = \cancel2 \times \dfrac{(8+ 3b)}{\cancel2}

\implies \tt Perimeter =8 + 3b

⠀⠀⠀⠀⠀⋆ Multiplying by \tt\frac{2}{2}

\implies \tt Perimeter =(8 + 3b) \times \dfrac{2}{2}

\implies \tt Perimeter =\bigg(\cancel8 \times \dfrac{1}{ \cancel2} + 3b \times\dfrac{1}{2} \bigg) \times 2

\implies \boxed{\tt Perimeter =2\bigg(4 + \dfrac{3b}{2} \bigg)}

Therefore, Option (C) is Correct.

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