Physics, asked by siddharthmalhotra7, 1 month ago

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Answered by pie96407
1

Answer:

(A) I1=VR1=125=2.4A

I2=VR2=1210=1.2A

I3=VR3=1230=0.4A

(b) Total current I=I1+I2+I3

=2.4A+1.2A+0.4A

(c ) Total effective resistance 1R=1R1+1R2+1R3

=15+110+130

=1030=13Ω

R=3Ω

Explanation:

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Answered by XXItzmoongirlXX
1

Explanation:

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