Answer this Don't spam Ans is 960
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No. of ways of selecting 3 bowlers out of 4 = 4C3 = 4
No. of ways of selecting 1 wicketkeeper from 2 = 2C1 =2
We have to calculate the ways for exactly 3 bowlers and 1 wicketkeeper.
Thus there is no need for any other wicketkeeper and bowlers thus the remaining players are 16 - (4 bowlers + 2 wicketkeepers) = 10
and we have to select 11 - ( 3 bowlers + 1 wicketkeeper) = 7
Thus no. of ways of selecting other players = 10C7 = 120
Thus total no. of ways = 120 × 4 × 2 = 960.
OK!!!!
manthan7445:
hmm
do u know my question's answer it is of the same chapter???
yes it is on Permutation and Combination
pls can u answer it?
what? i don't understand
See i have posted a question check it out in my profile.It is of Permutation and combinations
i posted my answer
is my answer helps you?
thanks for your answer but the question was to find for odd places of women
sitting
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