answer this. explain it.
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Answered by
3
Hii friend,
Here is your answer......
The correct answer is option (c) .
explanation:-
The incident angle is 60°
The angle is reflection is reducting 15° per medium and at last the angle of reflection at the medium 3 is 15°.
Then by using Snell's law,
Mu =>sin i /sin r
I=60°. r =15°
Then by applying,
mu => √3.
Hope this helps you a little!!!
Here is your answer......
The correct answer is option (c) .
explanation:-
The incident angle is 60°
The angle is reflection is reducting 15° per medium and at last the angle of reflection at the medium 3 is 15°.
Then by using Snell's law,
Mu =>sin i /sin r
I=60°. r =15°
Then by applying,
mu => √3.
Hope this helps you a little!!!
WhatsInTheName:
saka where the value of sin 15 u have used.
Answered by
5
hey the above final answer is correct but the assertion is not.
here is how to proceed.
first let the relative RI of 1 and 2 medium be
¶1
therefore ¶1 = sin i / sin r = sin 60 / sin 45=
...............(I)
now let ¶2 be the relative RI of 2 and 3 medium
therefore ¶2 = sin i/ sin r= sin 45/sin30 =
---------(2)
by dividing eqn 1 by 2
we get
but if we invert eqn 2nd we get med. 3 /med.2
= 1/√2
therefore finally med. 1/med. 3=
= √3/1= √3
hope you are satisfied.
mark brainlist if you find this helpful.
here is how to proceed.
first let the relative RI of 1 and 2 medium be
¶1
therefore ¶1 = sin i / sin r = sin 60 / sin 45=
...............(I)
now let ¶2 be the relative RI of 2 and 3 medium
therefore ¶2 = sin i/ sin r= sin 45/sin30 =
---------(2)
by dividing eqn 1 by 2
we get
but if we invert eqn 2nd we get med. 3 /med.2
= 1/√2
therefore finally med. 1/med. 3=
= √3/1= √3
hope you are satisfied.
mark brainlist if you find this helpful.
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