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1.by what least no .must 21600 be multiplied so as make it a perfect cube .
2. by what smallest no. by which 3600 be divided to make it a perfect cube
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2
Answer:
10,4
Step-by-step explanation:
21600=6×6×6×10×10
remaining 10 to make perfect square
3600÷1=3600 is the square of 60
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21600 is to be multiply with at least 10 to make a perfect cube.
21600= 6*6*6*10*10 { so after multiplying by 10 it will be a perfect cube..}
• firstly we need to find prime factors of 3600 and group factors in triplet.
3600= 2*2*2*2*3*3*5
as 2,3 and 5 not in triplet. therefore the required not be divided.
= 2x3x3x5x5 = 450
results number = 3600/450= 8
which is 2^3
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