Math, asked by KRRANthebro, 11 months ago

answer this fast
1.by what least no .must 21600 be multiplied so as make it a perfect cube .
2. by what smallest no. by which 3600 be divided to make it a perfect cube​

Answers

Answered by shashank2895
2

Answer:

10,4

Step-by-step explanation:

21600=6×6×6×10×10

remaining 10 to make perfect square

3600÷1=3600 is the square of 60


KRRANthebro: thanks
KRRANthebro: bhai 2nd wrong hai
shashank2895: its divided by 1
Answered by sneha486071
3

21600 is to be multiply with at least 10 to make a perfect cube.

21600= 6*6*6*10*10 { so after multiplying by 10 it will be a perfect cube..}

• firstly we need to find prime factors of 3600 and group factors in triplet.

3600= 2*2*2*2*3*3*5

as 2,3 and 5 not in triplet. therefore the required not be divided.

= 2x3x3x5x5 = 450

results number = 3600/450= 8

which is 2^3

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