Question

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Answer 1

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The total number of candidates who took the examination were 600

Solution:

Let the number of students be "x"

In an examination, the average was found to be 50 marks

The average is given as:

\begin{gathered}Average = \frac{sum\ of\ marks}{total\ students}\\\\50 = \frac{sum\ of\ marks}{x}\\\\sum\ of\ marks = 50x\end{gathered}

Average=

total students

sum of marks

50=

x

sum of marks

sum of marks=50x

After deducting computerization errors the marks of the 100 candidates had to be changed from 90 to 60 each and the average came down to 45 marks

Therefore, according to this condition,

\begin{gathered}\frac{50x - 100(90 - 60)}{x} = 45\\\\50x - 100 \times 30 = 45x\\\\50x - 3000 = 45x\\\\5x = 3000\\\\x = 600\end{gathered}

x

50x−100(90−60)

=45

50x−100×30=45x

50x−3000=45x

5x=3000

x=600

Thus the total number of candidates who took the examination were 600

Hope it helps ✨

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Answer 2