Question

Answer this fast....​

Answer 1

Step-by-step explanation:

(1+sec)cosec + cosec(1+sec) =2 cosec3(sec−1)

To find

L.H.S =R.H.S

Solution=>In the given equation we assume the value is given in thetha

from then question is:

(1+secθ) + cosecθ =2 cosec3θ(secθ−1)

cosecθ (1+secθ)

Solve L.H.S part:

⇒ (1+secθ) + cosecθ

cosecθ (1+secθ)

⇒ (1+secθ)2 + cosec2θ

θ cosecθ +(1+secθ)

⇒ cosec2θ + 1 + sec2θ

cosecθ+(1+secθ)

Solve R.H.S part:

⇒2 cosec3θ (secθ−1)

⇒2 1 ( 1 - 1 )

sin3θ cosθ

⇒2 1 ( 1 - cosθ )

sin3θ cosθ

⇒ 2−2cosθ

sin3θcosθ

sin3θcosθif we change the value is sin and cos so, it will prove the R.H.S part that's why we can say that:

L.H.S≠R.H.S