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1 / Sin10° - √3 / Cos10° = 4
=(cos10°-√3sin10°)/sin10°cos10°
=[2{(1/2)cos10°-(√3/2)sin10°}]/[(1/2)(2sin10°cos10°)]
=[(2×2)(sin30°cos10°-cos30°sin10°)]/sin20°
[∵, sin30°=1/2, cos30°=√3/2, 2sinФcosФ=sin2Ф]
=4sin(30°-10°)/sin20°
[∵, sinαcosβ-cosαsinβ=sin(α-β)]
=4sin20°/sin20°
=4
(Proved)
=(cos10°-√3sin10°)/sin10°cos10°
=[2{(1/2)cos10°-(√3/2)sin10°}]/[(1/2)(2sin10°cos10°)]
=[(2×2)(sin30°cos10°-cos30°sin10°)]/sin20°
[∵, sin30°=1/2, cos30°=√3/2, 2sinФcosФ=sin2Ф]
=4sin(30°-10°)/sin20°
[∵, sinαcosβ-cosαsinβ=sin(α-β)]
=4sin20°/sin20°
=4
(Proved)
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