Question

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A body of mass 50 kg has kinetic energy 600 J. The magnitude (numerical value) of the momentum of the body is​

Answer 1

Explanation:

Mass=40kg,v=1m/s,v=2m/s

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =(

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 2

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v 2

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v 2 −u

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v 2 −u 2

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v 2 −u 2 )

Mass=40kg,v=1m/s,v=2m/sAccording to the work-energy conversion theorem;Work done by the force= Change in Kinetic energy,Work done by the force =( 21 )×m×(v 2 −u 2 )Work done =0.5×40×(4−1)=60J

Answer 2

Given :-

• Mass (m) = 50 kg
• Kinetic Energy = 600 J

Need To Find :-

• Momentum of Body (p) = ?

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$\underline{\bigstar\:\textsf{Kinetic Energy of a body is equal to :}}$

$:\implies\red{\sf K.E.={}^{1}\!/{}_{2}\:mv^2}\\\\\\:\implies\sf 600 ={}^{1}\!/{}_{2} \times 50 \times v^2\\\\\\:\implies\sf 600 = 25 \times v^2\\\\\\:\implies\sf \bcancel\dfrac{600}{25} = v^2\\\\\\:\implies\sf 24 = v^2\\\\\\:\implies\sf \sqrt{24} = v\\\\\\:\implies\purple{\sf v = 4.899\:m/s}$

$\rule{200}{1}$

$\underline{\bigstar\:\textsf{Momentum of the body is equal to :}}$

$\dashrightarrow\pink{\sf \: \:Momentum=Mass \times Velocity}\\\\\\\dashrightarrow\sf \: \: p=50 \:kg \times 4.899 \:m/s\\\\\\\dashrightarrow\red{\sf \: \: p=244.95 \:kgm {s}^{ - 1}}$

⠀

$\therefore\:\underline{\textsf{Momentum of the body is equal to \textbf{244.95 kgms ^{ - 1} }}}.$