Question

Answer this fast and with statements and proper calculations​

Answer 1

Answer:

hey here is your answer

pls mark it as brainliest

Step-by-step explanation:

so basically for this sum we need to apply concept of arithmetic progression ie ap

so basically here

raj ran for 10 minutes on first day,on second day he ran for about 12 mins and thus on third day he ran 14 mins

so if we observe the time duration done by raj on these three days it is increasing by a factor of 2 mins each

so the common difference between each day of time duration is constant

so as common difference is constant

the sequence of time duration done by raj forms an ap

so for the above ap

a=t1=first term=1

d=common difference=2

n=no of day=10

so basically we need to find here tn ie no of minutes spent by raj on field on 10th day

thus using

tn=a+(n-1)d

=10+[(10-1)×2]

=10+(9×2)

=10+18

=28 mins

hence raj would take 28 minutes on 10th day if he increases his duration by 2 mins each upto 1pth day