Question

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Answer 1

c) 9.6kg answer is correct.

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Answer 2

Combustion of Ethylene can be written as:

C2H4 + 3 O2 → 2 CO2 + 2 H2O

0.028 kg (Molar mass of ethylene) needs 3 x 0.032 = 0.096 kg of oxygen.

1 kg of ethylene will need (0.096/0.028) = 3.42 kg of oxygen.

So, 2.8 kg of ethylene will need (3.42 x 2.8) = 9.6 kg of oxygen.

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