Question

Answer this fast if you don't know leave it​

Answer 1

Answer:

2

Step-by-step explanation:

hey

1-cos^2x=sin^2x

1-sin^2x=cos^x

so root of(sin^2 x)/sin x+root of cos^2 x/cosx

=sinx/sinx +cos x/cos x

=1+1=2

Answer 2

Hey Mate! ❤️

If you remember your trigonometry shortcuts, you know that 1−cos2x+cos2x=1. This means, then, that sin2x=1−cos2x (and that cos2x=1−sin2x).

So we can replace our 1−cos2x in our first numerator with sin2x. We can also replace our 1−sin2x in our second numerator with cos2x. Now our expression will look like this:

√sin2xsinx+√cos2xcosx

We also know that the square root of a value squared will cancel out to be the original value alone (for example,√22=2), so our expression will end up as:

=sinxsinx+cosxcosx

Or, in other words:

=1+1

=2

Our final answer is H, 2.

Hope it helps!