Question

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Answer 1

Answer:

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Explanation:

A rocket-propelled into space is a mass varying system as it losses the weight of the fuel burnt. Let the velocity of gas used for propelling be

′

v

g

′

& let the rate of decrease in mass of the body dm be

dt

dm

Then, by law of conservation of momentum since initial momentum is zero, dp=0

⇒ d(mv)=0

⇒ (dm)v+mdv=0

⇒ vdm=−mdv⇒ dm=−

v

dv

Integrating on both sides

v=v

g

(Inm)+c

⇒ v=−v

g

log

c

m+c

where c is a constant

Answer 2

A rocket-propelled into space is a mass varying system as it losses the weight of the fuel burnt. Let the velocity of gas used for propelling be 'v'g and let the rate of decrease in mass of the body dm be dm/dt

Then,by law of conservation of momentum since intial momentum is zero dp=0

→d(mv)=0

→(dm)v+mdv =0

→vdm= -mdv →dm = -dv/v

Integrating on both sides

V =Vg (Inm)+c

→V=-Vg LOGc m+c

Where C is a constant.

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