Question

answer this fast maths​

Answer 1

$\clubsuit\: \: \sf\bold{\pink{In\: question \: 13:-}}$

Given :-

$\sf \: p \: is \: ∥ \: to \: q$

To Find :-

$\sf \: Value \: of \: x$

Let's start

$\sf \: 2x = \: Angle \: 1 \:\sf\bold{\pink{[ Vertically \: opposite \: Angles ] }}$

$\sf \: 70 + 2x = 180 \:\sf\bold{\pink{[ Co-interior \: angles ] }}$

$2x = 180-70$

$x = 110$

So option d is correct

$\clubsuit\: \: \sf\bold{\blue{In\: question \: 14 :-}}$

Given :-

$\sf \: Angle \: AOC = 50$

To find :-

$\sf \: Angle \: AOD + Angle \: COB$

Let's start

$\sf \: Angle \: 1 = 50 \: \sf\bold{\blue{[Vertically \: opposite \: Angles]}}$

$\sf \: Sum \: of \: angles \: around \: a \: point \: is \: 360 \: so$

Angle AOC + Angle AOD + Angle DOB + Angle BOC = 360

50 + Angle AOD + 50 + Angle COB = 360

100 + Angle AOD + Angle COB = 360

Angle AOD + Angle COB = 360 - 100

Angle AOD + Angle COB = 260

So option d is correct