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as, Line graph of a linear eq.ⁿ has its ordinate(y-coordinate) always the three times of its abscissa(x-coordinate).
So, we can write that: 3x=y
or 3x–y=0
Now, for finding its solutions:
(1) Put, x=1
so, 3(1)=y
=>y=3
(2) Put, x=2
so, 3(2)=y
=>y=6
(3) Put, x=3
so, 3(3)=y
=>y=9
and so on...
Therefore, the three solutions of the line graph accordingly are:
(1)x=1, y=3
(2)x=2, y=6
(3)x=3, y=9
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