Question

Answer this fast ols​

Answer 1

Answer:

27

Step-by-step explanation:

$x-\frac{1}{x}$ =√3

$(x-\frac{1}{x}) ^{3}$=$3^{\frac{3}{2} }$

$x^{3}-3x^{2} \frac{1}{x} +3x\frac{1}{x^{2} }-\frac{1}{x^{3} } =3^{\frac{3}{2} }$

$x^{3}-3x+\frac{3}{x}-\frac{1}{x^{3} } =3^{\frac{3}{2} }$

$x^{3}-\frac{1}{x^{3} } - 3(x-\frac{1}{x} )=3^{\frac{3}{2} }$

$x^{3} -\frac{1}{x^{3} } -3\sqrt{3} =3^{\frac{3}{2} }$

$x^{3} -\frac{1}{x^{3} } =3^{\frac{3}{2} } +3^{\frac{3}{2} }$

$x^{3} -\frac{1}{x^{3} } =3^{3}=27$