answer this fast please please please please please please
Attachments:
![](https://hi-static.z-dn.net/files/dd2/dd3d2149eaa0f2c92cdea9cbde4316ba.jpg)
Answers
Answered by
2
consider triangle ACD and ABC
AB = AD (given)
‹DAC = ‹BAC (As AC bisects ‹A)
AC=AC (common)
TRIANGLE ACD = triangle ABC (BY SAS)
AB = AD (given)
‹DAC = ‹BAC (As AC bisects ‹A)
AC=AC (common)
TRIANGLE ACD = triangle ABC (BY SAS)
anusaji:
Plzz help with this q..
Similar questions