Question

answer this fast plz ​

Answer 1

Answer:

hope this answer will help u

Step-by-step explanation:

In ΔBEC, D is mid-point of BC and from converse of mid-point theorem. i.e. A line i.e. DF drawn through the mid-point D of BC and parallel to BE bisects the third side i.e. EC at F. Now, F becomes the mid-point of CE. ⇒ CF = 1 2 12 CE CF = 1 2 12 ( 1 2 12 AC) [E is mid-point of AC ⇒ AE = EC = 1 2 12 AC] ⇒ CF = 1 4 14 ACRead more on Sarthaks.com - https://www.sarthaks.com/784400/in-the-given-figure-ad-and-be-are-medians-of-abc-and-be-df-prove-that-cf-1-4ac