Question

answer this fastly it's argent​

Answer 1

Step-by-step explanation:

{(a+b)^a(a-b)^b}/[{(1/a)+(1/b)}^a][{(1/b)-(1/a)}^b]

={(a+b)^a}{(a-b)^b}/[{(a+b)/(ab)}^a][{(a-b)/(ab)}^b]

=[{(a+b)^a}{(a-b)^b}]×[{(ab)^a}{(ab)^b}]÷[{(a+b)^a}{(a-b}^b]

={(ab)^a}{(ab)^b}

=(ab)^(a+b)