Question

answer this fasttttt​

Answer 1

SOLUTION

GIVEN

a + b + c = 6

ab + bc + ca = 11

TO FIND VALUE OF

a^3 + b^3 + c^3 - 3abc

EXPLANATION

a + b + c = 6

(a + b + c) ^2 = 36

a^2 + b^2 + c^2 + 2 ( ab + bc + ca) = 36

a^2 + b^2 + c^2 + 2 ( 11) = 36

a^2 + b^2 + c^2 = 14

FORMULA OF a^3 + b^3 + c^3 - 3abc

( a + b + c) ( a^2 + b^2 + c^2 - ab - bc - ca)

( a + b + c) [ a^2 + b^2 + c^2 - (ab + bc + ca) ]

6 X (14 - 11 )

6 X 3 = 18

therefore,

a^3 + b^3 + c^3 - 3abc = 18

ANSWER = 18

FORMULA USED

• ( a + b + c)^2 =

a^2 + b^2 + c^2 + 2 ( ab + bc + ca)

• a^3 + b^3 + c^3 - 3abc =

( a + b + c) [ a^2 + b^2 + c^2 - ab - bc - ca]