Question

answer this Find the value of log4/5 (64/125)+log4/5 (1)​

Answer 1

Answer:

$log_{\frac{4}{5}}(\frac{64}{125})+log_{\frac{4}{5}}(1)=3$

Step-by-step explanation:

Formula used:

Product rule:

$log_a(MN)=log_aM+log_aN$

Value of $log_aa=1$

$Now\\\\log_{\frac{4}{5}}(\frac{64}{125})+log_{\frac{4}{5}}(1)\\\\by\:product\:rule\\\\=log_{\frac{4}{5}}(\frac{64}{125}*1)\\\\=log_{\frac{4}{5}}(\frac{4}{5})^3\\\\by\:power\:rule\\\\=3\:log_{\frac{4}{5}}(\frac{4}{5})\\\\=3(1)\\\\=3$