Answer this for 50 points! Metallic Carbonate "A" reacts with hydrochloric acid to form sodium Compound and liberate "B" gas. "B" reacts with slaked lime and form "C". Identify A, B, and C. Write suitable chemical equation.
Answers
hi mate,
Answer :
let,
A=Na2Co3,
B=Co2,
C=NaoH
And the suitable chemical equation is
NaoH+H2O+Co2=>Na2Co3+H2O
extra example....
Calcium carbonate gives carbon dioxide gas when reacts with hydrochloric acid.
CaCO 3 +2HCl⟶CaCl 2 +CO2 +H 2 O
Carbon dioxide turns lime water milky when passed through it because of formation of calcium carbonate.
When carbon dioxide; so formed; is passed through lime water, lime water turns milky because of the formation of calcium carbonate.
Ca(OH) 2 +CO 2→CaCO3 +H2O
On the electrolysis of brine, chlorine gas is deposited over anode which gives calcium oxychloride (Bleaching powder) on passing over slaked lime. The bleaching powder is used in disinfecting the drinking water.
Ca(OH) 2 +Cl 2⟶CaOCl 2 +H 2 O
Bleaching powder is used for disinfecting drinking water.
Therefore, metal carbonate X
′
is calcium carbonate.
Solution Y is lime water (Calcium hydroxide).
Gas G is chlorine gas.
Dry Y is dry calcium hydroxide (dry slaked lime).
Compound Z is bleaching powder (Calcium oxychloride).
I hope it helps you
Answer:
E.g., Zn(s) + 2HCl(aq) → ZnCl2 (aq) + H2(g)
To test the presence of H2 gas, bring a burning splinter near the mouth of the test tube where H2 gas is released, the match stick bums with a pop sound.Curd and sour substances contain acids which can react with copper vessels and brass to form toxic compounds.