Question

Answer this friends

Answer 1

HERE IS THE ANSWER FOR YOUR QUESTION;

◆The answer is D)3cm.◆

◆◆PROOF◆◆

WE know that OP=OQ 【Radius of same circle】........1)

Also, AP=AQ. 【By theorem】..........2)

And The perimeter of OPAQ is 26cm .......3)

And AP is 26. ........4)

By using 2) equation and 4) Equation.
we get.

AP=QA=10cm.

So, 26-20=6cm.

But OP=OQ by 1)

so,

OP=OQ= Diameter of the circle 【If assumed as straight】

So,

OP=OQ=6÷2

=3cm.

Hope it helps

Answer 2

Hey,
Ur answer is 3cm.
See....
OP=OQ(radius of the same circle)
AP=AQ(Triangle AOP is congruent to triangle AOQ)
So, now,
Since, perimeter =26cm.
So, OP+OQ+AP+AQ=26
Let OP=OQ be X,
So,
x+x+10+10=26 (AP=AQ=10)
2x=26-20
x=6/2
x=3cm.
Therefore the radius is 3cm.

Hope this helps you buddy!!
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