Question

answer this full worksheet!!​

Answer 1

Answer:

1. Given,

Base 1 (a) = 4.5cm

Base 2 (b) = 3.5 cm

Altitude = 7cm

We know that,

area of a trapezium =

$= > \frac{1}{2} h \times (a + b)$

Therefore area =

$\frac{1}{2} \times 7(4.5 + 3.5)cm ^{2} \\ = > \frac{1}{2} \times 7 \times 8 \\ = > 7 \times 4 = 28cm {}^{2}$

2. Given,

Diagonal 1 = 3.2m

Diagonal 2 = 5m

We know that area of rhombus

$= > \frac{d1 \times \: d 2}{2}$

$\frac{3.2 \times 5}{2} = \frac{16}{2} = 8m {}^{2}$

Answer 2

1. Given :-

Base 1 (a) = 4.5cm

Base 2 (b) = 3.5 cm

Altitude = 7cm

: We know that

area of a trapezium =

$=>12h×(a+b)= > \frac{1}{2} h \times (a + b)=>h×(a+b)$

Therefore area =

$12×7(4.5+3.5)cm2=>12×7×8=>7×4=28cm2\begin{lgathered}\frac{1}{2} \times 7(4.5 + 3.5)cm ^{2} \\ = > \frac{1}{2} \times 7 \times 8 \\ = > 7 \times 4 = 28cm {}^{2}\end{lgathered}$

2. Given :-

Diagonal 1 = 3.2m

Diagonal 2 = 5m

: We know that area of rhombus

$=>d1×d22= > \frac{d1 \times \: d 2}{2}=>$

$3.2×52=162=8m2\frac{3.2 \times 5}{2} = \frac{16}{2} = 8m {}^{2}$